Answer)
Null hypothesis Ho : P1 = P2
Alternate hypothesis Ha : P1 > P2
N1 = 3281, P1 = 60/3281
N2 = 9285, P2 = 120/9285
First we need to check the conditions of normality that is if n1p1 and n1*(1-p1) and n2*p2 and n2*(1-p2) all are greater than equal to 5 or not
N1*p1 = 60
N1*(1-p1) = 3221
N2*p2 = 120
N2*(1-p2) = 9165
All the conditions are met so we can use standard normal z table to conduct the test
Test statistics z = (P1-P2)/standard error
Standard error = √{p*(1-p)}*√{(1/n1)+(1/n2)}
P = pooled proportion = [(p1*n1)+(p2*n2)]/[n1+n2]
After substitution
Test statistics z = 2.22
From z table, P(Z>2.22) = 0.0132
So, P-Value = 0.0132
As the obtained P-Value is less than the given significance 0.05.
We reject the null hypothesis Ho.
We have enough evidence to conclude that seat belts are effective in preventing deaths.
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