A study of identity theft looked at how well consumers protect themselves from this increasingly prevalent crime. The behaviors of 61 college students were compared with the behaviors of 58 nonstudents. One of the questions was "When asked to create a password, I have used either my mother's maiden name, or my pet's name, or my birth date, or the last four digits of my social security number, or a series of consecutive numbers." For the students, 22 agreed with this statement while 27 of the nonstudents agreed.
Perform the chi-square test. (Round your χ2 to three decimal places and round your P-value to four decimal places.)
B) χ2 =
C) df=
D) P-value=
Reanalyze the data using the methods for comparing two proportions that we studied in the previous chapter. Compare the results and verify that the chi-square statistic is the square of the z statistic. (Test students who agreed minus nonstudents who agreed. Round your z to two decimal places and round your P-value to four decimal places.\
E) Z-value=
F) P-value=
applying chi square test:
Observed | Oi | student | non student | Total |
agreed | 22 | 27 | 49 | |
not agreed | 39 | 31 | 70 | |
Lawyer | 61 | 58 | 119 | |
Expected | Ei=row total*column total/grand total | student | non student | Total |
agreed | 25.118 | 23.882 | 49 | |
not agreed | 35.882 | 34.118 | 70 | |
Lawyer | 61 | 58 | 119 | |
chi square χ2 | =(Oi-Ei)2/Ei | student | non student | Total |
agreed | 0.3870 | 0.4070 | 0.794 | |
not agreed | 0.2709 | 0.2849 | 0.556 | |
Lawyer | 0.658 | 0.692 | 1.350 |
b)test statistic X2 =1.350
c)df=1
d) p value =0.2453
e ) z value =1.16
f) p value =0.2453
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