Question

Use the given data to find the minimum sample size required to
estimate the population proportion.

Margin of error: 0.04; confidence level: 95%; from a prior
study, is estimated by the decimal equivalent of
52%.

Answer #1

Solution :

Given that,

= 0.52

1 - = 0.48

margin of error = E = 0.04

At 95% confidence level the z is ,

= 1 - 95% = 1 - 0.95 = 0.05

/ 2 = 0.05 / 2 = 0.025

Z_{/2}
= Z_{0.025} = 1.96

sample size = n = (Z_{
/ 2} / E )^{2} *
* (1 -
)

= (1.96 / 0.04)^{2} * 0.52 * 0.48

= 599.29

**sample size = 600**

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