Determine the area under the standard normal curve that lies to the right of (a) Z = 1.52, (b) Z = 0.34, (c) Z= -0.71, and (d) Z = -1.87 .
Solution :
Using standard normal table ,
(a)
P(z > 1.52) = 1 - P(z < 1.52) = 1 - 0.9357 = 0.0643
The area under the standard normal curve that lies to the right of z = 1.52 is 0.0643
(b)
P(z > 0.34) = 1 - P(z < 0.34) = 1 - 0.6331 = 0.3669
The area under the standard normal curve that lies to the right of z = 0.34 is 0.3669
(c)
P(z > -0.71) = 1 - P(z < -0.71) = 1 - 0.2389 = 0.7611
The area under the standard normal curve that lies to the right of z = -0.71 is 0.7611
(d)
P(z > -1.87) = 1 - P(z < -1.87) = 1 - 0.0307 = 0.9693
The area under the standard normal curve that lies to the right of z = -1.87 is 0.9693
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