Translate the statement into confidence intervals. Approximate the level of confidence.
In a survey of 1062 in a country 78% said being able to speak the language is at the core of national identity . The surveys margin of error is +-3.9%.
The confidence interval for the proportion is (?,?)
Solution :
Given that,
n = 1062
Point estimate = sample proportion = = 0.78
1 - = 0.22
Margin of error = E = 0.039
A 95% confidence interval for population proportion p is ,
- E < p < + E
0.78 - 0.039 < p < 0.78 + 0.039
0.741 < p < 0.819
The confidence interval for the population proportion p is : (0.741 , 0.819) or (74.1% , 81.9%)
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