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To be on the safe side, 4000 voters were surveyed and 1300 were in favor of...

To be on the safe side, 4000 voters were surveyed and 1300 were in favor of gambling on sporting events. Give a 99% confidence interval for the tur proportion of voters in favor of sports gabling

Math   Statistics-And-Probability   
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Answer #1

Sample proportion = 1300 / 4000 = 0.325

99% confidence interval for p is

- Z * sqrt( ( 1 - ) / n) < p < + Z * sqrt( ( 1 - ) / n)

0.325 - 2.576 * sqrt( 0.325 * 0.675 / 4000) < p < 0.325 + 2.576 * sqrt( 0.325 * 0.675 / 4000)

0.306 < p < 0.244

99% CI is ( 0.306 , 0.244 )

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