Question

27. Find the critical values chi squared Subscript Upper L and chi squared Subscript Upper R for the given confidence level c and sample size n. cequals0.98, nequals23 chi squared Subscript Upper Lequals nothing (Round to three decimal places as needed.)

Answer #1

27)

Solution :

Given that,

n = 23

Degrees of freedom = df = n - 1 = 22

At 98% confidence level the
^{2} value is ,

= 1 - 98% = 1 - 0.98 = 0.02

/ 2 = 0.02 / 2 = 0.01

1 - / 2 = 1 - 0.01 = 0.99

^{2}_{L}
=
^{2}_{/2,df}
= 40.289

^{2}_{R}
=
^{2}_{1 -} _{
/2,df} = 9.542

Find the critical values chi squared Subscript Upper L and chi
squared Subscript Upper R for the given confidence level c and
sample size n. cequals0.9, nequals22 chi squared Subscript Upper
Lequals nothing (Round to three decimal places as needed.) chi
squared Subscript Upper Requals nothing (Round to three decimal
places as needed.)

Find the critical values chi Subscript Upper R Superscript 2χ2R
and chi Subscript Upper L Superscript 2χ2L for the given confidence
level c and sample size n.
c=0.80, n=17

Find the critical values
chi Subscript Upper R Superscript 2χ2R
and
chi Subscript Upper L Superscript 2χ2L
for the given confidence level c and sample size n.
cequals=0.950.95,
nequals=15

1) Find the critical values chi Subscript Upper R Superscript 2
and chi Subscript Upper L Superscript 2 for the given confidence
level c and sample size n. c 0.90, n=15
2) Use the confidence interval to find the margin of error and
the sample mean. ( left 0.672,0.850 )

Use the given information to find the number of degrees of?
freedom, the critical values chi Subscript Upper L Superscript 2
and chi Subscript Upper R Superscript 2?, and the confidence
interval estimate of sigma. It is reasonable to assume that a
simple random sample has been selected from a population with a
normal distribution. Nicotine in menthol cigarettes 99?%
?confidence; nequals30?, sequals0.24 mg. LOADING... Click the icon
to view the table of? Chi-Square critical values. dfequals nothing
?(Type a...

Find the critical values chi squared Subscript 1 minus alpha
divided by 2 and chi squared Subscript alpha divided by 2 for a
99% confidence level and a sample size of nequals20.

Use the given information to find the number of degrees of
freedom, the critical values chi Subscript Upper L Superscript 2
and chi Subscript Upper R Superscript 2, and the confidence
interval estimate of sigma. It is reasonable to assume that a
simple random sample has been selected from a population with a
normal distribution. Nicotine in menthol cigarettes 99%
confidence; n = 29, s = 0.29 mg.
df = ?
(Type a whole number.)
2χ2L = ?
(Round to...

Use the given information to find the number of degrees of
freedom, the critical values chi Subscript Upper L Superscript 2χ2L
and chi Subscript Upper R Superscript 2χ2R, and the confidence
interval estimate of sigma σ.
It is reasonable to assume that a simple random sample has been
selected from a population with a normal distribution.
Nicotine in menthol cigarettes 95% confidence; n=25,
s=0.22m
df= [ ] (type a whole number)
chi Subscript Upper L Superscript 2χ2L= [ ] (round...

Use the given information to find the number of degrees of
freedom, the critical values chi Subscript Upper L Superscript 2
and chi Subscript Upper R Superscript 2, and the confidence
interval estimate of sigma. It is reasonable to assume that a
simple random sample has been selected from a population with a
normal distribution.
Nicotine in menthol cigarettes 99% confidence; nequals23,
sequals0.22 mg.

Use the given information to find the number of degrees of
freedom, the critical values chi Subscript Upper L Superscript 2
and chi Subscript Upper R Superscript 2, and the confidence
interval estimate of sigma. It is reasonable to assume that a
simple random sample has been selected from a population with a
normal distribution. Platelet Counts of Women 99% confidence;
nequals23, sequals65.4.

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 8 minutes ago

asked 8 minutes ago

asked 20 minutes ago

asked 24 minutes ago

asked 26 minutes ago

asked 35 minutes ago

asked 45 minutes ago

asked 46 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago