Question

Exhibit E
Suppose a simple random sample of 150 students to study the proportion of students who live in dormitories indicates a sample proportion of 0.35.

Refer to Exhibit E. To construct a 95% confidence interval for the population proportion, p, the margin of error is:

Answer 1

Solution :

Given that,

Point estimate = sample proportion = = 0.35

1 - = 1 - 0.35 = 0.65

Z/2 = 1.96

Margin of error = E = Z / 2 * (( * (1 - )) / n)

= 1.96 * (((0.35 * 0.65) / 150)

Margin of error = E = 0.076

The margin of error is: 0.076