Given N~(5,1) Find the probability that P[X > 5 ] , P[3.5 < X < 5.5], and that P[X<2]
Solution :
Given that ,
mean = = 5
standard deviation = = 1
P(x > 5) = 1 - P(x < 5)
= 1 - P((x - ) / < (5 - 5) / 1)
= 1 - P(z < 0)
= 1 - 0.5
= 0.5
Probability = 0.5
P(3.5 < x < 5.5) = P((3.5 - 5)/ 1) < (x - ) / < (5.5 - 5) / 1) )
= P(-1.5 < z < 0.5)
= P(z < 0.5) - P(z < -1.5)
= 0.6915 - 0.0668
= 0.6247
Probability = 0.6247
P(x < 2) = P((x - ) / < (2 - 5) / 1)
= P(z < -3)
= 0.0013
Probability = 0.0013
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