Question

A sample mean, sample standard deviation, and sample size are given. Use the one-mean t-test to perform the required hypothesis test about the mean, μ, of the population from which the sample was drawn. Use the critical-value approach.

, , n = 11, H₀: μ = 18.7, H_a: μ ≠ 18.7, α = 0.05

Group of answer choices

Test statistic: t = 1.03. Critical values: t = ±2.201. Do not reject H₀. There is not sufficient evidence to conclude that the mean is different from .

Test statistic: t = 1.03. Critical values: t = ±2.201. Reject H₀. There is sufficient evidence to conclude that the mean is different from .

Test statistic: t = 1.03. Critical values: t = ±2.228. Do not reject H₀. There is not sufficient evidence to conclude that the mean is different from .

Test statistic: t = 1.03. Critical values: t = ±1.96. Reject H₀. There is sufficient evidence to conclude that the mean is different from .

Answer 1

Answer: Test statistic: t = 1.03. Critical values: t = ±2.228. Do not reject H0. There is not sufficient evidence to conclude that the mean is different from 18.7

Explanation: The degrees of freedom for one-mean t test= n – 1 =11- 1=10

Thus the critical value of t at 10 df and 0.05 level of significance = ±2.228.

Conclusion; The value of test statistic less than critical value of t. Hence we do not reject H0 and conclude that there is not sufficient evidence to conclude that the mean is different from 18.7