Claim: The mean pulse rate (in beats per minute) of adult males is equal to 69 bpm. For a random sample of 161 adult males, the mean pulse rate is 69.7 bpm and the standard deviation is 11.3 bpm. Find the value of the test statistic.
The value of the test statistic is ??
(Round to two decimal places as needed.)
SOLUTION
this is the two tailed test .
The null and alternative hypothesis is ,
H0 :
= 69
Ha :
69
Test statistic = z
= (
-
) /
/
n
= (69.7-69) / 11.3/
161
Z =0.79
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