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A survey is being planned to determine the mean amount of time corporation executives watch television....

A survey is being planned to determine the mean amount of time corporation executives watch television. A pilot survey indicated that the mean time per week is 15 hours, with a standard deviation of 2.5 hours. It is desired to estimate the mean viewing time within 30 minutes. The 99% level of confidence is to be used. (Use z Distribution Table.)

How many executives should be surveyed? (Round your z-score to 2 decimal places and round up your final answer to the next whole number.)

Math   Statistics-And-Probability   
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Answer #1

We have given here,              
              
Population standard deviation =   150 minutes (2.5 hours)
Margin of error =E=30 minutes
Level of significance =0.01
Z critical value is (by using Z table) =2.58

Sample size formula is

  

=165.87

  
              
Therefore, sample size will be approximately =166          

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