Question

A survey is being planned to determine the mean amount of time corporation executives watch television. A pilot survey indicated that the mean time per week is 15 hours, with a standard deviation of 2.5 hours. It is desired to estimate the mean viewing time within 30 minutes. The 99% level of confidence is to be used. (Use z Distribution Table.)

How many executives should be surveyed? (Round your z-score to 2 decimal places and round up your final answer to the next whole number.)

Answer #1

We have given here,

Population standard deviation = 150 minutes (2.5
hours)

Margin of error =E=30 minutes

Level of significance =0.01

Z critical value is (by using Z table) =2.58

Sample size formula is

=165.87

Therefore, sample size will be approximately =166

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