Question

In the week before and the week after a​ holiday, there were 10 comma 000 total​ deaths, and 4986 of them occurred in the week before the holiday. a. Construct a 95​% confidence interval estimate of the proportion of deaths in the week before the holiday to the total deaths in the week before and the week after the holiday. b. Based on the​ result, does there appear to be any indication that people can temporarily postpone their death to survive the​ holiday? a. nothingless thanpless than nothing ​(Round to three decimal places as​ needed.) b. Based on the​ result, does there appear to be any indication that people can temporarily postpone their death to survive the​ holiday?

Answer 1

a)

Sample proportion = 4986 / 10000 = 0.4986

95% confidence interval for p is

- Z * sqrt ( ( 1 - ) / n) < p < + Z * sqrt ( ( 1 - ) / n)

0.4986 - 1.96 * sqrt( 0.4986 * 0.5014 / 10000) < p < 0.4986 + 1.96 * sqrt( 0.4986 * 0.5014 / 10000)

0.489 < p < 0.508

b)

Since this interval contains 0.50, we do not have sufficient evidence to support the claim.