#Given:
mean=18
standard deviation==3
Margin of error=0.5
#=1-c%=1-0.98=0.02
Z/2=Z0.02/2=Z0.01=2.326
#value Z0.01 is obtain from standard normal table
Sample size=n
n=(Z/2*/ME)^2
n=(2.3263*3/0.5)^2=194.82
#Sample size =195
# 195 students should you choose to investigate
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