Question

Assume that a random sample is used to estimate a population proportion p. Find the margin...

Assume that a random sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. n equals 600 comma x equals 240 comma 90 % confidence The margin of error Eequals nothing. ​(Round to four decimal places as​ needed.)

Homework Answers

Answer #1

Solution :

Given that,

Point estimate = sample proportion = = x / n = 240 / 600 = 0.400

1 - = 0.600

Z/2 = 1.645

Margin of error = E = Z / 2 * (( * (1 - )) / n)

= 1.645 * (((0.400 * 0.600) / 600)

= 0.0329

Margin of error = E = 0.0329

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