Question

In a recent poll, 300 people were asked if they liked soccer, and 37% said they did. Based on this, construct a 90% confidence interval for the true population proportion of people who like soccer.

As in the reading, in your calculations:
--Use z = 1.645 for a 90% confidence interval
--Use z = 2 for a 95% confidence interval
--Use z = 2.576 for a 99% confidence interval.


Give your answers as decimals, to 4 decimal places.

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Answer 1

Given:

n = 300,   = 37% = 0.37, = 0.10

Calculation:

Critical value:

         …………Using standard Normal table

90% Confidence interval:

0.3242 < P < 0.4158

We are 90% confident that the true population proportion of people who like soccer is lies in this interval.