Use the normal approximation to find the indicated probability. The sample size is n, the population proportion of successes is p, and X is the number of successes in the sample. n = 81, p = 0.5: P(X ≥ 46)
Solution :
Given that,
p = 0.5
q = 1 - p =1-0.5=0.5
n = 81
Using binomial distribution,
= n * p = 81*0.5=40.5
= n * p * q = 81*0.5*0.5=4.5
Using continuity correction
,P(x >46 ) = 1 - P(x < 45.5)
= 1 - P((x - ) / < (45.5-40.5) / 4.5)
= 1 - P(z < 1.11)
Using z table
= 1-0.8665
probability= 0.1335
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