In computing an ANOVA involving four groups of 12 each, the following partially completed ANOVA table was given. Complete this table.
Source | SS | df | MS | F |
Between | 9 | |||
Within | ||||
Total | 20 | |||
(A) degree of freedom (between) = number of groups -1
it is given that number of groups = 4
this implies
df(between) = 4-1 = 3
(B) degree of freedom (within) = total number of elements - number of groups
it is given that number of groups = 4 and total number of elements = 4*12 = 48
this implies
df(within) = 48-4 = 44
(C) df(total) = df(between)+df(within) = 3 + 44 = 47
(D) SS(within) = SS(total) -SS(between)
using the data values given in the data table
SS(within) = 20-9 = 11
(E) MS(between) = SS(between)/df(between)
this implies
= 9/3
= 3
(F) MS(within) = SS(within)/df(within)
this implies
= 11/44
= 0.25
(G) F statistics = MS(between)/MS(within)
using the calculated values
this implies
= 3/0.25
= 12
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