Researchers collected data on the numbers of hospital admissions resulting from motor vehicle crashes and results are given below for Fridays on the 6th of a month and Fridays on the following 13th of the same month. Construct a 95% confidence interval estimate of the mean of the population of differences between hospital admissions on days that are Friday the 6th of a month and days that are Friday the 13th of a month. Use the confidence interval to test the claim that when the 13th day of a month falls on a Friday, the numbers of hospital admissions from motor vehicle crashes are not affected.
Friday the 6th {9, 6, 11, 11, 3, 5)
Friday the 13th {13,12,14,10,4,12)
1. What are the hypothesis for this test?
2. Find the value of the test statistic.
3. Identify critical values.
4. State the result of the test
Please explain.
Friday the 6th |
Friday the 13th |
Diff |
|
9 |
13 |
-4 |
|
6 |
12 |
-6 |
|
11 |
14 |
-3 |
|
11 |
10 |
1 |
|
3 |
4 |
-1 |
|
5 |
12 |
-7 |
|
Mean |
-3.33 |
||
Std Dev |
3.01 |
Alpha = 0.05
ZCritical = 1.96
95% CI for difference of means = -3.33 +/- 1.96*(3.01/61/2) ={-5.74, -0.92}
Null and Alternate Hypothesis
H0: µD = 0
Ha: µD <> 0
Test Statistic
t = -3.33/(3.01/61/2) = -2.71
Critical Values = -2.571, 2.571
Result
Since the test statistic is less than -2.571, we reject the null hypothesis
Conclusion
There is difference in hospital admissions if it is Friday 13th
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