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5.38 Find the 99th percentile of a normal random variable with μ=8 and σ2=9

5.38 Find the 99th percentile of a normal random variable with μ=8 and σ2=9

Math   Statistics-And-Probability   
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Answer #1

Given that,

mean = = 8

= 9

standard deviation = = 3

Using standard normal table,

P(Z < z) = 99%

= P(Z < z) = 0.99  

= P(Z <2.33 ) = 0.99

z =2.33 Using standard normal z table,

Using z-score formula  

x= z * +

x= 2.33 *3+8

x= 14.99=15 rounded

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