Question

A survey of 1,570 randomly selected adults showed that 541 of them have heard of a new electronic reader. The accompanying technology display results from a test of the claim that 34​% of adults have heard of the new electronic reader. Use the normal distribution as an approximation to the binomial​ distribution, and assume a 0.01 significance level to complete parts​ (a) through​ (e).

a. Is the test​ two-tailed, left-tailed, or​ right-tailed?

Right tailed test

​Left-tailed test

​Two-tailed test

b. What is the test​ statistic?

zequals=nothing

​(Round to two decimal places as​ needed.)

c. What is the​ P-value?

​P-value equals=nothing

​(Round to four decimal places as​ needed.)

d. What is the null hypothesis and what do you conclude about​ it?

Identify the null hypothesis.

A.

Upper H 0 : p less than 0.34H0: p<0.34

B.

Upper H 0 : p not equals 0.34H0: p≠0.34

C.

Upper H 0 : p greater than 0.34H0: p>0.34

D.

Upper H 0 : p equals 0.34H0: p=0.34

Choose the correct answer below.

A.

Reject

the null hypothesis because the​ P-value is less than or equal toless than or equal to the significance​ level,

alphaα.

B.

Fail to reject the null hypothesis because the​ P-value is greater than the significance​ level, alphaα.

C.

Fail to reject the null hypothesis because the​ P-value is less than or equal to the significance​ level, alphaα.

D.

Reject the null hypothesis because the​ P-value is greater than the significance​ level, alphaα.

e. What is the final​ conclusion?

A.There is not sufficient evidence to warrant rejection of the claim that 34% of adults have heard of the new electronic reader.

B.There is sufficient evidence to support the claim that 34% of adults have heard of the new electronic reader.

C.There is not sufficient evidence to support the claim that 34​% of adults have heard of the new electronic reader.

D.There is sufficient evidence to warrant rejection of the claim that 34% of adults have heard of the new electronic reader.

Answer 1