Q1. Customers arrive to a bank. The chance to leave
without receiving a service for every customer is 0.05. Answer the
following questions: [Hint this is Bernoulli trial with a
probability of success (leaving without receiving a service) is
0.05 and probability of failure (leaving after receiving a service)
is 0.95]
What is the probability that no customer will leave
without receiving a service for the next 10 customers?
What is the probability of that less than 3 customers
will leave without receiving a service for the next 10
customers?
What is the expected number of customers (mean) leave
without receiving a service for the first 100 arrivals?
What is the probability that the first customer leaves without receiving a service comes at the customer number 100?
What is the probability that the third customer leave without receiving a service comes at customer number 100?
What is the expected number of customer to see the first leave without receiving a service?
What is the variance for the number of trials before seeing the first leave without receiving a service?
1) probability that no customer will leave without receiving a service for the next 10 customers=(1-0.05)10 =0.5987
2) probability of that less than 3 customers will leave without receiving a service for the next 10 customers =P(X<3)
= =0.9885
3)
expected number of customers (mean) leave without receiving a service for the first 100 arrivals=np=100*0.05 =5
4)
probability that the first customer leaves without receiving a service comes at the customer number 100 =(0.95)99*0.05=0.000312
5)
probability that the third customer leave without receiving a
service comes at customer number 100
=99C2(0.05)3(0.95)97
=0.004187
6)
expected number of customer to see the first leave without receiving a service=1/p=1/0.05 =20
variance for the number of trials before seeing the first leave without receiving a service=(1-p)/p2 =380
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