Mendel crossed peas in such a way that 25% (or 145) of the 580
offspring peas were expected to
have yellow pod. Instead of getting 145 peas with yellow pods, he
obtained 152. Find probability that among the 580 offspring peas,
at least 152 have yellow pods.
solution:
the given information as follows:
p = 0.25
n = 580
n*p = 0.25*580 = 145
n(1-p) = 580*(1-0.25) = 435
since n*p and n(1-p) both are greater than 5 , we use normal approximation to binomial,
mean =
standard deviation =
we have to find the probability that atleast 152 have yellow pods = P(X > 152)
using continuity correction we have to find P(X > 151.5)
z score :
using the z table
P(X > 151.5) = 1 - value of z to the left of 0.62 = 1 - 0.7324 = 0.2676
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