A statistics teacher believes that the final exam grades for her class have a normal distribution with a mean of 80 and a standard deviation of 8. Answer the following: | ||||
(a) | Determine the z-score for a person from this population that has a test score of 66. Then find the z-score for someone whose test score is 95. | |||
(b) | If x represents a possible test score from this population, find P(x > 87). | |||
(c) | Find P(79 < x < 89) and write a sentence for the interpretation of this value. | |||
(d) | The top 10% of all people in this group have test scores high enough to earn an A. Determine the test score which is high enough to earn an A. | |||
Given that, mean = 80 and
standard deviation = 8
a) We want to find, z-score for test scores of 66 and 95
For x = 66
z = (66 - 80)/8 = -1.75
For x = 95
z = (95 - 80)/8 = 1.875
b)
=> P(X > 87) = 0.1894
c)
The probability that exam grade is between 79 and 89 is 0.4225
d) We want to find, the value of x such that, P(X > x) = 0.10
Test score = 90.24
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