Question

Elderly drivers. A polling agency interviews 866 American adults and finds that 546 think licensed drivers...

Elderly drivers. A polling agency interviews 866 American adults and finds that 546 think licensed drivers should be required to retake their road test once they reach 65 years of age. Round all answers to 4 decimal places.

1. Calculate the point estimate for the proportion of American adults that think licensed drivers should be required to retake their road test once they reach 65 years of age.  

2. Calculate the standard error for the point estimate you calculated in part 1.  

3. Calculate the margin of error for a 95% confidence interval for the proportion of American adults that think licensed drivers should be required to retake their road test once they reach 65 years of age.

4. What are the lower and upper limits for the 95% confidence interval.

(  ,  )

5. Based on a 95% confidence interval, does the poll provide convincing evidence that more than 70% of the population think that licensed drivers should be required to retake their road test once they turn 65?

A. No, because our confidence interval includes 70%.  
B. Yes, because a wider confidence interval would include 70%.
C. No, because the plausible values for this percentage are all less than 70%.
D. Yes, because 70% is more than the values in our confidence interval.

6. Use the information from the polling agency to determine the sample size needed to construct a 90% confidence interval with a margin of error of no more than 4.1%. For consistency, use the reported sample proportion for the planning value of p* (rounded to 4 decimal places) and round your Z-value to 3 decimal places. Your answer should be an integer.

Homework Answers

Answer #1

1) point estimate for the proportion =0.6305

2) standard error for the point estimate =0.0164

3) margin of error =0.0321

4) lower and upper limits for the 95% confidence interval =0.5984 ; 0.6626

5)

C. No, because the plausible values for this percentage are all less than 70%.

6)

here margin of error E = 0.041
for90% CI crtiical Z          = 1.645
estimated proportion=p= 0.6305
required sample size n =         p*(1-p)*(z/E)2= 376.00
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
In a survey of 1019 ​adults, a polling agency​ asked, "When you​ retire, do you think...
In a survey of 1019 ​adults, a polling agency​ asked, "When you​ retire, do you think you will have enough money to live comfortably or not. Of the 1019 ​surveyed, 535 stated that they were worried about having enough money to live comfortably in retirement. Construct a 99​% confidence interval for the proportion of adults who are worried about having enough money to live comfortably in retirement. A. There is 99​% confidence that the true proportion of worried adults is...
In a survey of 1001 ​adults, a polling agency​ asked, "When you​ retire, do you think...
In a survey of 1001 ​adults, a polling agency​ asked, "When you​ retire, do you think you will have enough money to live comfortably or not. Of the 10011 ​surveyed, 522 stated that they were worried about having enough money to live comfortably in retirement. Construct a 9090​% confidence interval for the proportion of adults who are worried about having enough money to live comfortably in retirement.
In a survey of 10101010 ​adults, a polling agency​ asked, "When you​ retire, do you think...
In a survey of 10101010 ​adults, a polling agency​ asked, "When you​ retire, do you think you will have enough money to live comfortably or not. Of the 10101010 ​surveyed, 532532 stated that they were worried about having enough money to live comfortably in retirement. Construct a 9090​% confidence interval for the proportion of adults who are worried about having enough money to live comfortably in retirement. Click here to view the standard normal distribution table (page 1). LOADING... Click...
In 2015 as part of the General Social Survey, 1383 randomly selected American adults responded to...
In 2015 as part of the General Social Survey, 1383 randomly selected American adults responded to this question: “Some countries are doing more to protect the environment than other countries. In general, do you think that America is doing more than enough, about the right amount, or too little?” Of the respondents, 436 replied that America is doing about the right amount. What is the 95% confidence interval for the proportion of all American adults who feel that America is...
Is college worth it? Among a simple random sample of 341 American adults who do not...
Is college worth it? Among a simple random sample of 341 American adults who do not have a four-year college degree and are not currently enrolled in school, 154 said they decided not to go to college because they could not afford school. 1. Calculate a 95% confidence interval for the proportion of Americans who decide to not go to college because they cannot afford it, and interpret the interval in context. Round to 4 decimal places. (_,_) 2. Suppose...
It is thought that 65% of American adults drink alcohol of one kind or another. Are...
It is thought that 65% of American adults drink alcohol of one kind or another. Are college students like other American adults? A university dean wants to estimate the percentage of students at her university who drink alcohol of one kind or another. If she wants to estimate this percentage to within ±3% with 95% confidence, how many students should she sample? In a random sample of 1200 college students, 828 say they drink alcohol of one kind or another....
1. A Gallup poll asked 1200 randomly chosen adults what they think the ideal number of...
1. A Gallup poll asked 1200 randomly chosen adults what they think the ideal number of children for a family is. Of this sample, 53% stated that they thought 2 children is the ideal number. Construct and interpret a 95% confidence interval for the proportion of all US adults that think 2 children is the ideal number. 2. There were 2430 Major League Baseball games played in 2009, and the home team won the game in 53% of the games....
(a) A newspaper conducted a statewide survey concerning the 1998 race for state senator. The newspaper...
(a) A newspaper conducted a statewide survey concerning the 1998 race for state senator. The newspaper took a SRS of 1200 registered voters and found that 620 would vote for the Republican candidate. Let pp represent the proportion of registered voters in the state who would vote for the Republican candidate. How large a sample nn would you need to estimate pp with a margin of error 0.01 with 95 percent confidence? Use the guess p=.5p=.5 as the value of...
In what follows use any of the following tests/procedures: Regression, confidence intervals, one-sided t-test, or two-sided...
In what follows use any of the following tests/procedures: Regression, confidence intervals, one-sided t-test, or two-sided t-test. The procedures should be done with 5% P-value or 95% confidence interval. # of OpenLab visits Final grade 2 40 8 85 10 80 9 84 15 90 7 72 5 50 4 59 8 85 10 70 7 66 7 70 5 63 4 60 4 59 11 79 3 82 9 90 10 82 9 76 14 85 6 73 5...
An experiment on memory was performed, in which 16 subjects were randomly assigned to one of...
An experiment on memory was performed, in which 16 subjects were randomly assigned to one of two groups, called "Sentences" or "Intentional". Each subject was given a list of 50 words. Subjects in the "Sentences" group were told to form multiple sentences, each using at least two words from the list, and to keep forming sentences until all the words were used at least once. Subjects in the "Intentional" group were told to spend five minutes memorizing as many of...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT