Consider the following hypotheses:
H0: μ = 9,100
HA: μ ≠ 9,100
The population is normally distributed with a population standard
deviation of 700. Compute the value of the test statistic and the
resulting p-value for each of the following sample
results. For each sample, determine if you can "reject/do not
reject" the null hypothesis at the 10% significance level.
(You may find it useful to reference the appropriate
table: z table or t
table) (Negative values should be
indicated by a minus sign. Round intermediate calculations to at
least 4 decimal places. Round "test statistic" values to 2 decimal
places and "p-value" to 4 decimal
places.)
Test statistic | p-value | |||
a. | x−x− = 9,190; n = 105 | (Click to select) Reject H0 Do not reject H0 | ||
b. | x−x− = 9,190; n = 255 | (Click to select) Reject H0 Do not reject H0 | ||
c. | x−x− = 8,830; n = 37 | (Click to select) Reject H0 Do not reject H0 | ||
d. | x−x− = 8,860; n = 37 | (Click to select) Do not reject H0 Reject H0 | ||
As population standard deviation is known, we will use z distribution to find the test statistics
a.
P value is
As P value greater than alpha=0.1, we fail to reject the null hypothesis
So Do not reject H0
b.
P value is
As P value is less than alpha=0.1, we reject the null hypothesis
So Reject H0
c.
P value is
As P value is less than alpha=0.1, we reject the null hypothesis
So Reject H0
d.
As P value is less than alpha=0.1, we reject the null hypothesis
So Reject H0
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