Question

1. A recent study focused on the number of times men and women who live alone...

1.

A recent study focused on the number of times men and women who live alone buy take-out dinner in a month. Assume that the distributions follow the normal probability distribution. The information is summarized below.


  Statistic Men Women
  Sample mean 24.71    21.94   
  Population standard deviation 5.53    4.71   
  Sample size 36    41   

  

At the .01 significance level, is there a difference in the mean number of times men and women order take-out dinners in a month? Hint: Consider the "Men" data as the first sample.

  

(a) Compute the value of the test statistic. (Round your answer to 3 decimal places.)

  

  Value of the test statistic   


(b) What is your decision regarding on null hypothesis?


  The decision is (Click to select)do not rejectreject the null hypothesis that the means are the same.


(c) What is the p-value? (Round your answer to 4 decimal places.)


  p-value   

2.

Clark Heter is an industrial engineer at Lyons Products. He would like to determine whether there are more units produced on the night shift than on the day shift. A sample of 55 day-shift workers showed that the mean number of units produced was 342, with a population standard deviation of 26. A sample of 63 night-shift workers showed that the mean number of units produced was 349, with a population standard deviation of 32 units.

At the .10 significance level, is the number of units produced on the night shift larger?
(1) This is a (Click to select)twoone-tailed test.
(2)

The decision rule is to reject H0:μd≥μnH0: μd⁢≥μn if z < . (Negative value should be indicated by a minus sign. Round your answer to 2 decimal places.)

(3)

The test statistic is z = . (Negative value should be indicated by a minus sign. Round your answer to 2 decimal places.)

(4) What is your decision regarding H0H0?
  
(Click to select)Reject.Do not reject.

3.

A coffee manufacturer is interested in whether the mean daily consumption of regular-coffee drinkers is less than that of decaffeinated-coffee drinkers. Assume the population standard deviation for those drinking regular coffee is 1.39 cups per day and 1.55 cups per day for those drinking decaffeinated coffee. A random sample of 45 regular-coffee drinkers showed a mean of 4.59 cups per day. A sample of 39 decaffeinated-coffee drinkers showed a mean of 5.19 cups per day.

Use the .05 significance level.
(1) This is a (Click to select)onetwo-tailed test.
(2)

The decision rule is to reject H0 : μr ≥ μd if z < . (Negative value should be indicated by a minus sign. Round your answer to 2 decimal places.)

(3)

The test statistic is z = . (Negative value should be indicated by a minus sign. Round your answer to 2 decimal places.)

(4) What is your decision regarding H0 ?
  
(Click to select)Do not reject.Reject.
(5) The p-value is . (Round your answer to 4 decimal places.)

Homework Answers

Answer #1

1.

  Statistic Men Women
  Sample mean 24.71    21.94   
  Population standard deviation 5.53    4.71   
  Sample size 36    41   

  

significance level = .01

Two tail test

  

(a) Compute the value of the test statistic. (Round your answer to 3 decimal places.)

  

  Value of the test statistic 2.349
(b) What is your decision regarding on null hypothesis?
  The decision is do not reject the null hypothesis that the means are the same.
(c) What is the p-value? (Round your answer to 4 decimal places.)
  p-value 0.0246
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