Suppose a population of scores x is normally distributed with μ = 30 and σ = 12. Use the standard normal distribution to find the probability indicated. (Round your answer to four decimal places.)
Pr(24 ≤ x ≤ 42)
Solution :
Given that ,
mean = = 30
standard deviation = = 12
= P[(24 - 30 / 12) (x - ) / (42 - 30 / 12) ]
= P(-0.5 z 1)
= P(z 1) - P(z -0.5)
= 0.8413 - 0.3085
= 0.5328
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