Question

Complete parts​ (a) and​ (b) using the probability distribution below. The number of overtime hours worked in one week per employee Overtime hours 0 1 2 3 4 5 6 Probability 0.031 0.057 0.160 0.299 0.222 0.144 0.087 (a) Find the​ mean, variance, and standard deviation of the probability distribution. Find the mean of the probability distribution. Find the mean of the probability distribution. mu equals =

Answer 1

Solution :

Mean = X * P(X)

= 0 * 0.031 + 1 * 0.057 + 2 * 0.160 + 3 * 0.299 + 4 * 0.222 + 5 * 0.144 + 6 * 0.087 = 3.404

mean = 3.404

variance =  X ² * P(X) - ²

= 0 * 0.031 + 1 * 0.057 + 2² * 0.160 + 3² * 0.299 + 4² * 0.222 + 5² * 0.144 + 6² * 0.087 - 3.404³

= 2.085

Standard deviation = = 1.444