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To study what proportion of students will take statistics at UCW, undergrad students were repeatedly sampled...

  1. To study what proportion of students will take statistics at UCW, undergrad students were repeatedly sampled with samples of size 36. The sampling distribution shows that 80% of them must take this course to complete a degree. What is the probability that more than 85% of the UCW students take statistics? What is the standard error of the population proportion?

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To study what proportion of students will take statistics at UCW, undergrad students were repeatedly sampled with samples of size 36. The sampling distribution shows that 80% of them must take this course to complete a degree. What is the probability that more than 85% of the UCW students take statistics? What is the standard error of the population proportion? (4 marks)

Normal approximation to binomial distribution used.

n=36, p=0.80

standard error = sqrt( p*(1-p)/n) = sqrt(0.8*0.2/36) = 0.0667

z value for the proportion 0.85, z = (0.85-0.80)/0.0667 = 0.75 ( 2 decimals)

P( p>0.85) = P( z > 0.75)

=0.2266

The required probability = 0.2266

Excel function used to get probability: =1-NORM.S.DIST(0.75,TRUE)

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