Result:
To study what proportion of students will take statistics at UCW, undergrad students were repeatedly sampled with samples of size 36. The sampling distribution shows that 80% of them must take this course to complete a degree. What is the probability that more than 85% of the UCW students take statistics? What is the standard error of the population proportion? (4 marks)
Normal approximation to binomial distribution used.
n=36, p=0.80
standard error = sqrt( p*(1-p)/n) = sqrt(0.8*0.2/36) = 0.0667
z value for the proportion 0.85, z = (0.85-0.80)/0.0667 = 0.75 ( 2 decimals)
P( p>0.85) = P( z > 0.75)
=0.2266
The required probability = 0.2266
Excel function used to get probability: =1-NORM.S.DIST(0.75,TRUE)
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