76 | Statistic | |
64 | Sample Size | |
62 | Sample Mean | |
81 | Sample Standard Deviation (SD) | |
70 | ||
72 | Minimum | |
81 | First Quartile (Q1) | |
63 | Median (Q2) | |
67 | Third Quartile (Q3) | |
77 | Maximum | |
Sample size is 10
Sample mean is
Sample Standard deviation is calculated as below
Create the following table.
data | data-mean | (data - mean)2 |
76 | 4.7 | 22.09 |
64 | -7.3 | 53.29 |
62 | -9.3 | 86.49 |
81 | 9.7 | 94.09 |
70 | -1.3 | 1.69 |
72 | 0.7 | 0.49 |
81 | 9.7 | 94.09 |
63 | -8.3 | 68.89 |
67 | -4.3 | 18.49 |
77 | 5.7 | 32.49 |
Find the sum of numbers in the last column to get.
So
The minimum is the smallest value in a data set.
Ordering the data from least to greatest, we get:
62 63 64 67 70 72 76 77 81 81
So, the minimum is 62.
The first quartile (or lower quartile or 25th percentile) is the median of the bottom half of the numbers. So, to find the first quartile, we need to place the numbers in value order and find the bottom half.
62 63 64 67 70 72 76 77 81 81
So, the bottom half is
62 63 64 67 70
The median of these numbers is 64.
The median is the middle number in a sorted list of numbers. So, to find the median, we need to place the numbers in value order and find the middle number.
Ordering the data from least to greatest, we get:
62 63 64 67 70 72 76 77 81 81
As you can see, we do not have just one middle number but we have a pair of middle numbers, so the median is the average of these two numbers:
Median=
The third quartile (or upper quartile or 75th percentile) is the median of the upper half of the numbers. So, to find the third quartile, we need to place the numbers in value order and find the upper half.
62 63 64 67 70 72 76 77 81 81
So, the upper half is
72 76 77 81 81
The median of these numbers is 77.
The maximum is the greatest value in a data set.
Ordering the data from least to greatest, we get:
62 63 64 67 70 72 76 77 81 81
So, the maximum is 81.
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