Question

The distribution of political affiliation in California is shown in the table below.

Party	Expected Percent	Expected Frequency
Democrat	44%
Republican	35%
Independent/Other	21%

Suppose a random sample of 800 Californians who own their own homes are surveyed. The table below shows the results of the survey. Fill in the expected frequencies in the above table.

Party	Frequency
Democrat	247
Republican	297
Independent/Other	256

Test the if the distribution is as expected at the 5% significance level.

Test statistic (Round to 2 decimal places):

p-value (Round to 2 decimal places):

Answer 1

The hypothesis are

H0 : The distribution is as expected.

H1: The distribution is not as expected.

The test statistic is,

Here N = 800

Expected Frequency = E = n*p

Party	Observed Frequency (O)	Expected Percent	Expected Frequency (E)
Democrat	247	0.44	352	31.32
Republican	297	0.35	280	1.03
Independet/Other	256	0.21	168	46.10
Total				78.45

Hence, = 78.45

df = n -1 = 3-1 = 2

p value = p ( > 78.45 ) =  0.00 -----( using excel formula " =chisq.dist.rt( 78.45, 2)" )

Here p value < ( 0.05 ) .

Hence we reject null hypothesis.

Conclusion : The distribution is not as expected.