A coin is loaded so that the probability of occurrence of a face is 3 times that of a cross. Calculate the variance of the number of crosses if this coin is tossed twice.
Answer with up to 4 decimals.
A coin is tossed, there are two chances one is face and other is cross.
Let probability of occurrence cross comes is = p then
probability of occurrence of face is 3 times that of cross = 3p
Now we know that sum of all probabilities must be 1
p+3p = 1
4p = 1
p= 1/4
Probability of occurrence of cross = p = 1/4 = 0.26
Coin tosses twice , n= 2
Let X is random variable such that after tossing coin face comes or cross comes with probability of occurrence of crosses is 1/4
X follows Binomial Distribution
X ~ Binomial(n=2, p= 0.25)
We know variance of Binomial Distribution is given by
Varianceof X = Var(X) = np(1-p) = 2*0.25*(1-0.25)
Var(X) = 0.3750
Variance of number of crosses if this coin tosses twice is 0.3750
Get Answers For Free
Most questions answered within 1 hours.