Question

A group of 40 students were asked to catch a dropping ruler with their dominant hand and then with their non-dominant hand. The average distance until they catch the ruler is summarized as follows:

Dominant hand: Average=5.98, standard deviation=2.02

Non-Dominant hand: Average=6.08, standard deviation=2.46

Difference: Average= -0.10, standard deviation=2,33

Assuming that the data are normal, we want to test the claim that there is no difference between the mean distance for dominant and non-dominant hand. Use a 0.10 level of significance. Round your answer to 3 decimal places.

Group of answer choices

p-value=0.787, evidence support claim

p-value=0.787, evidence not support claim

p-value=0.843, evidence support claim

p-value=0.843, evidence not support claim

p-value=0.002, evidence not support claim

Answer 1

To test , Ho:

From given information output for given test is as follows:

Two-Sample T-Test and CI

Sample N Mean StDev SE Mean
1 40 5.98 2.02 0.32
2 40 6.08 2.46 0.39
Difference = mu (1) - mu (2)
Estimate for difference: -0.100000
90% CI for difference: (-0.938191, 0.738191)
T-Test of difference = 0 (vs not =): T-Value = -0.20 P-Value = 0.843 DF = 75

Where P Value=0.843 < 0.10 (alpha level)

# We reject Ho

# P value= 0.843,evidence not support claim is the correct answer.