Server response time is an important quality characteristic (CTQ). As an engineer you are interested to check whether the response time is significantly different/higher/lower from 100 milliseconds for given cases below. If the test statistics (Z0) is known, find the P-values for the following alternative hypotheses (μ ≠ 100, μ > 100, μ < 100)
NOTE: PLEASE COMPLETE THIS TASK USING MICROSOFT WORD OR SOME OTHER DIGITAL CONTENT EDITOR.
H0: μ = 100
H1: μ ≠ 100.
(a) Z0 = 1.86
(b) Z0 = −2.05
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H0: μ = 100
H1: μ > 100.
(c) Z0 = 2.50
(d) Z0 = −1.95
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H0: μ = 100
H1: μ < 100.
(e) Z0 = −2.35
(f) Z0 = −1.99
H0: μ = 100
H1: μ ≠ 100.
(a) Z0 = 1.86
p-value = 2 * P(Z > 1.86) = 2 * 0.0314 = 0.0628
=> p-value = 0.0628
(b) Z0 = −2.05
p-value = 2 * P(Z < -2.05) = 2 * 0.0202 = 0.0404
=> p-value = 0.0404
H0: μ = 100
H1: μ > 100.
(c) Z0 = 2.50
p-value = P(Z > 2.50) = 0.0062
=> p-value = 0.0062
(d) Z0 = −1.95
p-value = P(Z > -1.95) = 0.9745
=> p-value = 0.9744
H0: μ = 100
H1: μ < 100.
(e) Z0 = −2.35
p-value = P(Z < -2.35) = 0.0094
=> p-value = 0.0094
(f) Z0 = −1.99
p-value = P(Z < -1.99) = 0.0233
=> p-value = 0.0233
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