A Tim Horton's manager claims that more than 75% of customers purchase a coffee when they visit the store. We take a random sample of 225 customers and that 180 of them purchased a coffee. We would like to conduct a hypothesis test to determine whether there is significant evidence to support the manager's claim. The P-value for the appropriate hypothesis test is:
Solution :
This is the right tailed test .
The null and alternative hypothesis is
H0 : p = 0.75
Ha : p > 0.75
n = 225
x = 180
= x / n = 180 / 225 = 0.8
P0 = 0.75
1 - P0 = 0.25
z = - P0 / [P0 * (1 - P0 ) / n]
= 0.8 - 0.75 / [(0.75 * 0.25) / 225]
= 1.73
Test statistic = 1.73
P(z > 1.75) = 1 - P(z < 1.75) = 1 - 0.9599 = 0.0401
P-value = 0.0401
The P-value for the appropriate hypothesis test is 0.0401 .
= 0.05
P-value <
Reject the null hypothesis .
There sufficient evidence to that the significant evidence to support the manager's claim .
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