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Mars candy claims that 16% of all M&Ms are green. Assume that the M&Ms in a...

Mars candy claims that 16% of all M&Ms are green. Assume that the M&Ms in a 1 pound bag form a simple random sample of all M&Ms that are green. The bag we examine contains 318 M&Ms. let p^ be the proportion of sampled M&Ms that are green. what is the probability that p^ is less than 0.18?( That is, what is the probability that the bag contains less than 18% blue M&Ms?)
Math   Statistics-And-Probability   
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Answer #1

Given that, proportion of green M&M, p = 0.16

Sample size, n = 318

P( < A) = P(Z < (A - )/)

= p = 0.16

=

=

= 0.0206

P( < 0.18) = P(Z < (0.18 - 0.16)/0.0206)

= P(Z < 0.97)

= 0.8340

Probability that the bag contains less than 18% green M&Ms = 0.8340

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