Question

You work for a consumer watchdog publication and are testing the advertising claims of a tire...

You work for a consumer watchdog publication and are testing the advertising claims of a tire manufacturer. The manufacturer claims that the life spans of the tires are normally​ distributed, with a mean of​ 40,000 miles and a standard deviation of 40004000 miles. You test 16 tires and get the following life spans. Complete parts​ (a) through​ (c) below. 48,819  40,986 28,175  37,525  29,515 41,602 38,865 37,866 23,405 30,245 38,601 33,815 30,521 37,289 37,018  44,084

​(a) Draw a frequency histogram to display these data. Use five classes. Choose the correct answer below.

Is it reasonable to assume that the life spans are normally​ distributed? Why? Choose the correct answer below.

A. Yes, because the histogram is symmetric and​ bell-shaped.

B. ​Yes, because the histogram is neither symmetric nor​ bell-shaped.

C. No, because the histogram is symmetric and​ bell-shaped.

D. No, because the histogram is neither symmetric nor​ bell-shaped.

​(b) Find the mean of your sample. ​(Round to one decimal place as​ needed.)

Find the standard deviation of your sample. ​(Round to one decimal place as​ needed.)

Homework Answers

Answer #1
23,405
28,175
29,515
30,245
30,521
33,815
37,018
37,289
37,525
37,866
38,601
38,865
40,986
41,602
44,084
48,819

Range=48819-23405=25414

No. of class=5

Class width=25414/5=5082.8

so taking Class width=5100

Frequency Distribution

Class Width Frequency
23400-28500 2
28500-33600 3
33600-38700 6
38700-43800 3
43800-48900 2

a.) Frequency Histogram

Ans: A.Yes, because the histogram is symmetric and​ bell-shaped.

b.)Mean=36146

Standard Deviation=5626.3 (using excel.)

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A manufacturer claims that the life span of its tires is 52,000 miles. You work for...
A manufacturer claims that the life span of its tires is 52,000 miles. You work for a consumer protection agency and you are testing these tires. Assume the life spans of the tires are normally distributed. You select 100 tires at random and test them. The mean life span is 51.831 miles. Assume sigma = 800. Complete parts​ (a) through​ (c). (a) Assuming the​ manufacturer's claim is​ correct, what is the probability that the mean of the sample is 51,831...
A manufacturer claims that the life span of its tires is 51,000 miles. You work for...
A manufacturer claims that the life span of its tires is 51,000 miles. You work for a consumer protection agency and you are testing these tires. Assume the life spans of the tires are normally distributed. You select 100 tires at random and test them. The mean life span is 50,723 miles. Assume sigmaσequals=800. Complete parts​ (a) through​ (c). ​(a) Assuming the​ manufacturer's claim is​ correct, what is the probability that the mean of the sample is 50 comma 72350,723...
A manufacturer claims that the life span of its tires is 48,000 miles. You work for...
A manufacturer claims that the life span of its tires is 48,000 miles. You work for a consumer protection agency and you are testing these tires. Assume the life spans of the tires are normally distributed. You select one hundred tires at random and test them. The mean life span is 47,858 miles. Assume sigmaσequals=900 Complete parts​ (a) through​ (c). ​(a) Assuming the​ manufacturer's claim is​ correct, what is the probability that the mean of the sample is 47,858 miles...
A manufacturer claims that the life span of its tires is 50,000 miles. You work for...
A manufacturer claims that the life span of its tires is 50,000 miles. You work for a consumer protection agency and you are testing these tires. Assume the life spans of the tires are normally distributed. You select 100 tires at random and test them. The mean life span is 49 comma 785 49,785 miles. Assume sigma σ equals = 800 (ROUND TO FOUR DECIMALS)
A manufacturer claims that the life span of its tires is 52 comma 00052,000 miles. You...
A manufacturer claims that the life span of its tires is 52 comma 00052,000 miles. You work for a consumer protection agency and you are testing these tires. Assume the life spans of the tires are normally distributed. You select 100100 tires at random and test them. The mean life span is 51 comma 79951,799 miles. Assume sigma?equals=700700. Complete parts? (a) through? (c). ?(a) Assuming the? manufacturer's claim is? correct, what is the probability that the mean of the sample...
A manufacturer claims that the life span of its tires is 52 comma 000 miles. You...
A manufacturer claims that the life span of its tires is 52 comma 000 miles. You work for a consumer protection agency and you are testing these tires. Assume the life spans of the tires are normally distributed. You select 100 tires at random and test them. The mean life span is 51 comma 729 miles. Assume sigmaequals900. Complete parts​ (a) through​ (c). ​(a) Assuming the​ manufacturer's claim is​ correct, what is the probability that the mean of the sample...
Tire Life Prompt: A major tire manufacturer claims their heavy-duty truck tires have an average usage...
Tire Life Prompt: A major tire manufacturer claims their heavy-duty truck tires have an average usage life of 71,000 miles. The shipping department of the company you work for has been using these tires for several years and feels they are not getting the mileage promised. The manager pulled 25 maintenance records and found an average tire life of 68,050 miles, with a standard deviation of 11,602 miles. He asks you to conduct a test of hypothesis to determine if...
A tire manufacturer claims that his tires have a mean life of 60,000 miles when used...
A tire manufacturer claims that his tires have a mean life of 60,000 miles when used under normal driving conditions. A firm that requires a larger number of these tires wants to test the claim. If the claim is correct, the firm will purchase the manufacturer’s tires; otherwise, the firm will seek another supplier. Now a random sample of 100 tires is taken and the mean and standard deviation of the 100 tires are found. Using these sample results, a...
A tire manufacturer claims that his tires have a mean life of 60,000 miles when used...
A tire manufacturer claims that his tires have a mean life of 60,000 miles when used under normal driving conditions. A firm that requires a larger number of these tires wants to test the claim. If the claim is correct, the firm will purchase the manufacturer’s tires; otherwise, the firm will seek another supplier. Now a random sample of 100 tires is taken and the mean and standard deviation of the 100 tires are found. Using these sample results, a...
A tire manufacturer claims that his tires have a mean life of 60,000 miles when used...
A tire manufacturer claims that his tires have a mean life of 60,000 miles when used under normal driving conditions. A firm that requires a larger number of these tires wants to test the claim. If the claim is correct, the firm will purchase the manufacturer’s tires; otherwise, the firm will seek another supplier. Now a random sample of 100 tires is taken and the mean and standard deviation of the 100 tires are found. Using these sample results, a...