Question

The following information was obtained from a sample of 37 homes on the market. The square footage of each home was recorded.

Mean square footage: x =1796.4

Sample Standard deviation: s =120.3

A statistics student used the sample information to estimate with 95% confidence by creating a Z interval. Was this the appropriate procedure to use? Why or why not? Explain in words.

[NOTE: DO NOT compute the confidence interval]

Answer 1

No, this is not appropriate procedure to use.

To create a Z interval we need sample size, mean, population standard deviation and the critical value.

But, here in this problem, we are given sample size, mean square footage and sample standard deviation.

That means we cannot creat a Z interval by using mean square footage and sample standard deviation. We only need mean and population standard deviation, which are not given.

That is why this is not appropriate procedure to use.

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