Question
A poll of 2 comma 047 randomly selected adults showed that 94% of them own cell...
A poll of 2 comma 047 randomly selected adults showed that 94% of them own cell phones. The technology display below results from a test of the claim that 95% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.01 significance level to complete parts (a) through (e). Test of pequals0.95 vs pnot equals0.95 Sample X N Sample p 95% CI Z-Value P-Value 1 1933 2 comma 047 0.944309 (0.931253,0.957365) negative 1.18 0.237 a. Is the test two-tailed, left-tailed, or right-tailed?
Homework Answers
Answer #1
Not the answer you're looking for?
Similar Questions
A poll of 2 comma 085 randomly selected adults showed that 94% of them own cell...
A poll of 2 comma 085 randomly selected adults showed that 94%
of them own cell phones. The technology display below results from
a test of the claim that 91% of adults own cell phones. Use the
normal distribution as an approximation to the binomial
distribution, and assume a 0.05 significance level to complete
parts (a) through (e). Test of pequals0.91 vs pnot equals0.91
Sample X N Sample p 95% CI Z-Value P-Value 1 1957 2 comma 085
0.938609 (0.928306,0.948913)
A poll of 2 comma 059 randomly selected adults showed that 93% of them own cell...
A poll of 2 comma 059 randomly selected adults showed that 93%
of them own cell phones. The technology display below results from
a test of the claim that 94% of adults own cell phones. Use the
normal distribution as an approximation to the binomial
distribution, and assume a 0.01 significance level to complete
parts (a) through (e). Test of pequals0.94 vs pnot equals0.94
Sample X N Sample p 95% CI Z-Value P-Value 1 1909 2 comma 059
0.927149 (0.912396,0.941902)...
A poll of 2,024 randomly selected adults showed that 94% of them own cell phones. The...
A poll of 2,024 randomly selected adults showed that 94% of
them own cell phones. The technology display below results from a
test of the claim that 90% of adults own cell phones. Use the
normal distribution as an approximation to the binomial
distribution, and assume a 0.01
significance level to complete parts (a) through (e).
Test of
pequals=0.9 vs p≠0.9
Sample
X
N
Sample p
95% CI
Z-Value
P-Value
1
1904
2,024
0.940711
(0.927190,0.954233)
6.11
0.000
a. Is the...
A poll of 2,133 randomly selected adults showed that 94% of them own cell phones. The...
A poll of 2,133 randomly selected adults showed that 94% of
them own cell phones. The technology display below results from a
test of the claim that 92% of adults own cell phones. Use the
normal distribution as an approximation to the binomial
distribution, and assume a 0.01
significance level to complete parts (a) through (e).
Test
of
pequals
0.92vs
pnot equals
0.92
Sample
X
N
Sample p
95% CI
Z-Value
P-Value
1
1996
2 comma 133
0.935771
(0.922098,0.949444
)...
A poll of 2 comma 1172,117 randomly selected adults showed that 9191% of them own cell...
A poll of
2 comma 1172,117
randomly selected adults showed that
9191%
of them own cell phones. The technology display below results
from a test of the claim that
9393%
of adults own cell phones. Use the normal distribution as an
approximation to the binomial distribution, and assume a
0.010.01
significance level to complete parts (a) through (e).
Test of
pequals=0.930.93
vs
pnot equals≠0.930.93
Sample
X
N
Sample p
95% CI
Z-Value
P-Value
1
19241924
2 comma 1172,117
0.9088330.908833
(0.8927190.892719,0.9249480.924948)...
a poll of 2039 randomly selected adults showed that 96% of them own cell phones. the...
a poll of 2039 randomly selected adults showed that
96% of them own cell phones. the technology display below results
from a test of a claim that 92% of adults own cell phones. use the
normal distribution as an approximation to the binomial
distribution, and assume a 0.01 significance level to complete
parts (a) through (e)
a) is the test two-tailed, left-tailed, or right-tailed
b) the test statistic is ( rounded two decimals)
c) the p- value ( rounded three...
A poll of 2,061 randomly selected adults showed that 97% of them own cell phones. The...
A poll of 2,061 randomly selected adults showed that 97% of them
own cell phones. The technology display below results from a test
of the claim that 94% of adults own cell phones. Use the normal
distribution as an approximation to the binomial distribution, and
assume a 0.01 significance level to complete parts (a) through (e).
Show your work. ***Correct answers are in BOLD (how do we
get those answers)
Test of p=0.94 vs p≠0.94
X= 1989, N= 2061, Sample...
12. A poll of 2,108 randomly chosen adults showed 93% of them own cell phones. The...
12. A poll of 2,108 randomly chosen adults showed 93% of them
own cell phones. The claim was 91% of all adults own a cell
phone.
a. Based on the results above, state your decision and show how
you arrived at it. (4 points)
b. State your conclusion. (3 points)
c. Write a confidence statement that correctly interprets the
confidence interval. (3 points)
d. In terms of your data, discuss the type of error you could
have made and why....
A survey of 1,570 randomly selected adults showed that 541 of them have heard of a...
A survey of 1,570 randomly selected adults showed that 541 of
them have heard of a new electronic reader. The accompanying
technology display results from a test of the claim that 34% of
adults have heard of the new electronic reader. Use the normal
distribution as an approximation to the binomial distribution, and
assume a 0.01 significance level to complete parts (a) through
(e).
a. Is the test two-tailed, left-tailed, or right-tailed?
Right tailed test
Left-tailed test
Two-tailed test
b....
In a recent poll of 755 randomly selected adults, 587 said that it is morally wrong...
In
a recent poll of 755 randomly selected adults, 587 said that it is
morally wrong to not report all income on tax returns. Use a 0.05
significance level to test claim that 75% of adults say that it is
morally wrong to not report all income on tax returns. Identify the
null hypothesis, test statistic, P-value, and final conclusion that
addresses the original claim. Use the normal distribution as an
approximation of the binomial distribution.
ADVERTISEMENT
Need Online Homework Help?
Get Answers For Free
Most questions answered within 1 hours.
ADVERTISEMENT
Active Questions
asked 17 minutes ago
asked 33 minutes ago
asked 33 minutes ago
asked 50 minutes ago
asked 1 hour ago
asked 1 hour ago
asked 1 hour ago
asked 1 hour ago
asked 1 hour ago
asked 1 hour ago
asked 1 hour ago
asked 2 hours ago