Question

A poll of 2 comma 047 randomly selected adults showed that 94% of them own cell phones. The technology display below results from a test of the claim that 95% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.01 significance level to complete parts (a) through (e). Test of pequals0.95 vs pnot equals0.95 Sample X N Sample p 95% CI Z-Value P-Value 1 1933 2 comma 047 0.944309 (0.931253,0.957365) negative 1.18 0.237 a. Is the test two-tailed, left-tailed, or right-tailed?

Answer #1

A poll of 2 comma 085 randomly selected adults showed that 94%
of them own cell phones. The technology display below results from
a test of the claim that 91% of adults own cell phones. Use the
normal distribution as an approximation to the binomial
distribution, and assume a 0.05 significance level to complete
parts (a) through (e). Test of pequals0.91 vs pnot equals0.91
Sample X N Sample p 95% CI Z-Value P-Value 1 1957 2 comma 085
0.938609 (0.928306,0.948913)

A poll of 2 comma 059 randomly selected adults showed that 93%
of them own cell phones. The technology display below results from
a test of the claim that 94% of adults own cell phones. Use the
normal distribution as an approximation to the binomial
distribution, and assume a 0.01 significance level to complete
parts (a) through (e). Test of pequals0.94 vs pnot equals0.94
Sample X N Sample p 95% CI Z-Value P-Value 1 1909 2 comma 059
0.927149 (0.912396,0.941902)...

A poll of 2,024 randomly selected adults showed that 94% of
them own cell phones. The technology display below results from a
test of the claim that 90% of adults own cell phones. Use the
normal distribution as an approximation to the binomial
distribution, and assume a 0.01
significance level to complete parts (a) through (e).
Test of
pequals=0.9 vs p≠0.9
Sample
X
N
Sample p
95% CI
Z-Value
P-Value
1
1904
2,024
0.940711
(0.927190,0.954233)
6.11
0.000
a. Is the...

A poll of 2,133 randomly selected adults showed that 94% of
them own cell phones. The technology display below results from a
test of the claim that 92% of adults own cell phones. Use the
normal distribution as an approximation to the binomial
distribution, and assume a 0.01
significance level to complete parts (a) through (e).
Test
of
pequals
0.92vs
pnot equals
0.92
Sample
X
N
Sample p
95% CI
Z-Value
P-Value
1
1996
2 comma 133
0.935771
(0.922098,0.949444
)...

A poll of
2 comma 1172,117
randomly selected adults showed that
9191%
of them own cell phones. The technology display below results
from a test of the claim that
9393%
of adults own cell phones. Use the normal distribution as an
approximation to the binomial distribution, and assume a
0.010.01
significance level to complete parts (a) through (e).
Test of
pequals=0.930.93
vs
pnot equals≠0.930.93
Sample
X
N
Sample p
95% CI
Z-Value
P-Value
1
19241924
2 comma 1172,117
0.9088330.908833
(0.8927190.892719,0.9249480.924948)...

a poll of 2039 randomly selected adults showed that
96% of them own cell phones. the technology display below results
from a test of a claim that 92% of adults own cell phones. use the
normal distribution as an approximation to the binomial
distribution, and assume a 0.01 significance level to complete
parts (a) through (e)
a) is the test two-tailed, left-tailed, or right-tailed
b) the test statistic is ( rounded two decimals)
c) the p- value ( rounded three...

A poll of 2,061 randomly selected adults showed that 97% of them
own cell phones. The technology display below results from a test
of the claim that 94% of adults own cell phones. Use the normal
distribution as an approximation to the binomial distribution, and
assume a 0.01 significance level to complete parts (a) through (e).
Show your work. ***Correct answers are in BOLD (how do we
get those answers)
Test of p=0.94 vs p≠0.94
X= 1989, N= 2061, Sample...

12. A poll of 2,108 randomly chosen adults showed 93% of them
own cell phones. The claim was 91% of all adults own a cell
phone.
a. Based on the results above, state your decision and show how
you arrived at it. (4 points)
b. State your conclusion. (3 points)
c. Write a confidence statement that correctly interprets the
confidence interval. (3 points)
d. In terms of your data, discuss the type of error you could
have made and why....

A survey of 1,570 randomly selected adults showed that 541 of
them have heard of a new electronic reader. The accompanying
technology display results from a test of the claim that 34% of
adults have heard of the new electronic reader. Use the normal
distribution as an approximation to the binomial distribution, and
assume a 0.01 significance level to complete parts (a) through
(e).
a. Is the test two-tailed, left-tailed, or right-tailed?
Right tailed test
Left-tailed test
Two-tailed test
b....

In
a recent poll of 755 randomly selected adults, 587 said that it is
morally wrong to not report all income on tax returns. Use a 0.05
significance level to test claim that 75% of adults say that it is
morally wrong to not report all income on tax returns. Identify the
null hypothesis, test statistic, P-value, and final conclusion that
addresses the original claim. Use the normal distribution as an
approximation of the binomial distribution.

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