13. A 0.01 significance level is used for a hypothesis test of the claim that when parents use a particular method of genderselection, the proportion of baby girls is greater than 0.5. Assume that sample data consists of 55 girls in 100 births, so the sample statistic of 11/20 results in a z score that is 1 standard deviation above 0. Complete parts (a) through (h) below
A. Identify the null hypothesis and the alternative hypothesis. Choose the correct answer below.
A.Upper H 0: p ≠0.5
Upper H 1: p>0.5
B.Upper H 0: p=0.5
Upper H 1: p≠0.5
C.Upper H 0: p=0.5
Upper H 1: p<0.5
D.Upper H 0: p=0.5
Upper H 1: p>0.5
b. What is the value of α?
a=
(Type an integer or a decimal.)
c. What is the sampling distribution of the sample statistic?
Student (t) distribution
Normal distribution.
X2
d. Is the test two-tailed, left-tailed, or right-tailed?
Left-tailed
Two-tailed
Right-tailed
e. What is the value of the test statistic?
The test statistic is____
(Type an integer or a decimal.)
f. What is the P-value?
The P-value is____
(Round to four decimal places as needed.)
G. What are the critical value(s)?
The critical value(s) is/are____
(Round to two decimal places as needed. Use a comma to separate answers as needed.)
h. What is the area of the critical region?
The area is ____
(Round to two decimal places as needed.)
a)
The null and alternative hypothesis is
D.Upper H 0 : p = 0.5
Upper H 1 : p > 0.5
b)
Level of significance = = 0.01
c)
The sampling distribution of the sample statistic is Normal distribution.
d)
Right-tailed.
Because the alternative hypothesis has greater than sign.
e)
Sample size = n = 100
x = 55
Test statistic is
f)
P-value = P(Z > 1) = 0.1587
g)
Critical value = 2.32
h)
The area > 2.32 is critical region.
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