Suppose that an anxiety measure has a mean of 114 and SD of 20. The researcher only wants to work with 33% of the lower participants. What is the smallest average score the researcher should consider with a sample size of 30?
Solution,
Given that,
mean = = 114
standard deviation = = 20
n = 30
= = 114
= / n = 20 / 30 = 3.65
Using standard normal table,
P(Z < z) = 33%
= P(Z < z) = 0.33
= P(Z < -0.44) = 0.33
z = -0.44
Using z-score formula
= z * +
= -0.44 * 3.65 + 114
= 112.39
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