Question

A hat contains 10,000 balls. A random sample of 100 balls is selected from the hat....

A hat contains 10,000 balls. A random sample of 100 balls is selected from the hat. 17 of the selected balls are red, 27 are green and 56 are black. Construct a 96% confidence interval estimate for the percentage of green balls in the hat.

Homework Answers

Answer #1

Sample proportion for green balls = = 27/100 = 0.27

96% confidence interval for p is

- Z/2 * sqrt ( ( 1 - ) / n ) < p < + Z/2 * sqrt ( ( 1 - ) / n )

0.27 - 2.0537 * sqrt( 0.27 * 0.73 / 100) < p < 0.27 + 2.0537 * sqrt( 0.27 * 0.73 / 100)

0.179 < p < 0.361

96% CI is (0.179 , 0.361) = (17.9 , 36.1) %

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
There are 2 hats. Each hat contains red balls and blue balls. The first hat contains...
There are 2 hats. Each hat contains red balls and blue balls. The first hat contains 9875 balls. The second hat contains 11,375 balls. A random sample is chosen from the first hat. This sample contains 56 red balls and 89 blue balls. A random sample is chosen from the second hat. This sample contains 74 red balls and 85 blue balls. At a 1% significance level, use the p-value method to test the claim that the percentage of red...
An urn contains 17 white balls and 9 green balls. A sample of seven is selected...
An urn contains 17 white balls and 9 green balls. A sample of seven is selected at random. What is the probability that the sample contains at least one green ball? a) 1.0000 b) 0.8307 c) 0.9704 d) 0.0000 e) 0.1693 f) None of the above.
An urn contains 11 amber balls and 17 black balls. Two balls are selected at random,...
An urn contains 11 amber balls and 17 black balls. Two balls are selected at random, without replacement, and removed from the urn. The colors of the two balls removed are not observed. A third ball is then drawn from the urn at random. Find the probability that the third ball removed from the urn is amber.
2. Box A contains 10 red balls, and 15 green balls. Box B contains 12 red...
2. Box A contains 10 red balls, and 15 green balls. Box B contains 12 red balls and 17 balls green. A ball is taken randomly from box A and then returned to box B. From box B a random ball is drawn. a) Determine the chance that two green balls are taken. b) Determine the chance that 1 red ball is drawn and 1 green ball is taken
A box contains 8 red and 5 white balls. 8 balls are selected at random, without...
A box contains 8 red and 5 white balls. 8 balls are selected at random, without replacement. Find the probability that 3 white balls are selected.
A jar contains 30 red balls and 20 white balls. Twenty-five balls are randomly selected from...
A jar contains 30 red balls and 20 white balls. Twenty-five balls are randomly selected from the jar with replacement. What is the probability that a red ball was selected more than 20 times? Answer: (The answer was wrong) 0.009 A jar contains 30 red balls and 20 white balls. Twenty-five balls are randomly selected from the jar without replacement. What is the probability that the selection contains more than 20 red balls? Answer: (The answer was wrong) 0.0006
A box contains 5 blue balls, 8 red balls, 10 green balls. Ten balls are selected...
A box contains 5 blue balls, 8 red balls, 10 green balls. Ten balls are selected from the box simultaneously. Find the expected number of colors that appear on at least three of the ten balls. I have the answer but don't understand where it comes from.
An urn contains 1 white, 2 black, 3 red, and 4 green balls. If 6 balls...
An urn contains 1 white, 2 black, 3 red, and 4 green balls. If 6 balls are selected randomly (without replacement) and X represents the number of selections that are either red or green, find: (a) the probability mass function for X. (b) the expected value of X (calculate this value directly by using the probability mass function from part a).
This problem involves minitab so please show steps: A box contains r = 6 red balls...
This problem involves minitab so please show steps: A box contains r = 6 red balls and b = 36 black balls with N = r+b =42 balls. Now you sample n = 6 balls at random from this box and count number of red balls (X) in your sample. The probability distribution of X is known as hyper geometric distribution. Using Minitab, construct pdf and cdf of X
A basket contains 3 green and 2 yellow balls. One ball will be selected at random...
A basket contains 3 green and 2 yellow balls. One ball will be selected at random and then not replaced. Then a second ball will be randomly selected from the basket. G= # of green balls observed during the experiment. 16a) Draw a tree diagram with probabilities written on the branches. At the end of each branch, identify each outcome of the Sample Space and its probability. 16b) Write the pmf (probability mass function) of in column format, identifying its...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT