Question

In a recent survey of 1004 individuals, 442 disapproved of the way Congress handled health care...

In a recent survey of 1004 individuals, 442 disapproved of the way Congress handled health care reform. Find the 95% confidence interval for the true population proportion of individuals that disapproved of the way Congress handled health care reform.

Homework Answers

Answer #1

Solution :

Given that,

n = 1004

x = 442

Point estimate = sample proportion = = x / n = 0.440

1 - = 1- 440 = 0.560

Z/2 = 1.96

Margin of error = E = Z / 2 * (( * (1 - )) / n)

= 1.96 * (0.440(1-0.440) /1004 )

= 0.030

A 95% confidence interval for population proportion p is ,

- E < p < + E

0.440 - 0.030 < p <0.440 + 0.030

0.410< p < 0.470

The 95% confidence interval for the population proportion p is : 0.410 and 0.470

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
For many years businesses have struggled with the rising cost of health care. But recently, the...
For many years businesses have struggled with the rising cost of health care. But recently, the increases have slowed due to less inflation in health care prices and employees paying for a larger portion of health care benefits. A recent Mercer survey showed that 58% of U.S. employers were likely to require higher employee contributions for health care coverage in 2009. Suppose the survey was based on a sample of 691 companies. Compute the margin of error and a 95%...
In survey of 952 respondents, 620 of them voted in a recent electionFind a 95% confidence...
In survey of 952 respondents, 620 of them voted in a recent electionFind a 95% confidence interval estimate for the true population proportion that voted in this election
For many years businesses have struggled with the rising cost of health care. But recently, the...
For many years businesses have struggled with the rising cost of health care. But recently, the increases have slowed due to less inflation in health care prices and employees paying for a larger portion of health care benefits. A recent Mercer survey showed that 52% of U.S. employers were likely to require higher employee contributions for health care coverage. Suppose the survey was based on a sample of 700 companies. Compute the margin of error and a 95% confidence interval...
For many years businesses have struggled with the rising cost of health care. But recently, the...
For many years businesses have struggled with the rising cost of health care. But recently, the increases have slowed due to less inflation in health care prices and employees paying for a larger portion of health care benefits. A recent Mercer survey showed that 52% of U.S. employers were likely to require higher employee contributions for health care coverage. Suppose the survey was based on a sample of 400 companies. Compute the margin of error and a 95% confidence interval...
For many years businesses have struggled with the rising cost of health care. But recently, the...
For many years businesses have struggled with the rising cost of health care. But recently, the increases have slowed due to less inflation in health care prices and employees paying for a larger portion of health care benefits. A recent Mercer survey showed that 52% of U.S. employers were likely to require higher employee contributions for health care coverage. Suppose the survey was based on a sample of 400 companies. Compute the margin of error and a 95% confidence interval...
In a survey of 2572 adults in a recent​ year, 1308 say they have made a...
In a survey of 2572 adults in a recent​ year, 1308 say they have made a New​ Year's resolution. Construct​ 90% and​ 95% confidence intervals for the population proportion. Interpret the results and compare the widths of the confidence intervals. (round to three decimal places as needed) The​ 90% confidence interval for the population proportion p is? The 95% confidence interval for the population proportion p is?
a survey was conducted that asked 1004 people, about how many books they have read in...
a survey was conducted that asked 1004 people, about how many books they have read in the past year, Results indicated that x = 11.3 books and s = 16.6books. a) Construct a 95% confidence interval for the mean number of books read all or part of the way through during the preceding year and interpret it. gives you this:
For many years businesses have struggled with the rising cost of health care. But recently, the...
For many years businesses have struggled with the rising cost of health care. But recently, the increases have slowed due to less inflation in health care prices and employees paying for a larger portion of health care benefits. A recent Mercer survey showed that 52% of U.S. employers were likely to require higher employee contributions for health care coverage. Suppose the survey was based on a sample of 1,000 companies. Compute the margin of error and a 95% confidence interval...
A survey commissioned by a health care group reported that 16% of New Zealanders consume five...
A survey commissioned by a health care group reported that 16% of New Zealanders consume five or more servings of soft drinks per week. The data were obtained by an online survey of 2,006 randomly selected New Zealanders over 15 years of age. Find a 95% confidence interval for the proportion of New Zealanders who report that they consume five or more servings of soft drinks per week. (Round your answers to four decimal places.)
4. A survey of 35 individuals reveals that the proportion of people in a residential area...
4. A survey of 35 individuals reveals that the proportion of people in a residential area who patronize a particular supermarket is 0.42; a repeat of the survey in the following year, using 52 individuals finds that the proportion is 0.56. Find a 95% confidence interval for the difference in sample proportions. (3) PLEASE HELP!