In a recent survey of 1004 individuals, 442 disapproved of the way Congress handled health care reform. Find the 95% confidence interval for the true population proportion of individuals that disapproved of the way Congress handled health care reform.
Solution :
Given that,
n = 1004
x = 442
Point estimate = sample proportion = = x / n = 0.440
1 - = 1- 440 = 0.560
Z/2 = 1.96
Margin of error = E = Z / 2 * (( * (1 - )) / n)
= 1.96 * (0.440(1-0.440) /1004 )
= 0.030
A 95% confidence interval for population proportion p is ,
- E < p < + E
0.440 - 0.030 < p <0.440 + 0.030
0.410< p < 0.470
The 95% confidence interval for the population proportion p is : 0.410 and 0.470
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