Assume that x has a normal distribution with the specified mean and standard deviation. Find the indicated probability. (Enter a number. Round your answer to four decimal places.)
μ = 28; σ = 3.6
P(x ≥ 30) =
Solution :
Given that ,
mean = = 28
standard deviation = = 3.6
P(x 30 ) = 1 - P(x 30 )
= 1 - P[(x - ) / (30-28) /3.6 ]
= 1 - P(z 0.56)
= 1- 0.7123 = 0. 2877
probability = 0.2877
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