Question

1. Based on historical data, your manager believes that 34% of the company's orders come from first-time customers. A random sample of 91 orders will be used to estimate the proportion of first-time-customers. What is the probability that the sample proportion is greater than than 0.41?

2.  According to a 2009 Reader's Digest article, people throw away approximately 18% of what they buy at the grocery store. Assume this is the true proportion and you plan to randomly survey 84 grocery shoppers to investigate their behavior. What is the probability that the sample proportion is between 0.06 and 0.13?

Answer 1

(there are more than 1 different questions, as per policy i am answering first question)

P(z<Z) table :

1.

mean p = 0.34

SD = [p*(1-p)/n]^0.5

= [0.34*(1-0.34)/91]^0.5

= 0.0497

ANSWER : 0.0795

(please UPVOTE)