Calculate the p-value for the following conditions and determine whether or not to reject the null hypothesis.
a) one-tail test,
zx =1.70, and α =0.10 |
b) one-tail test,
z = negative −2.45 and α = 0.02 |
c) two-tail test,
zx = 2.40, and α= .10 |
d) two-tail test, zx = −1.24, and α = 0.05 |
a) one-tail test,
zx =1.70, and α =0.10
P-value = P(Z > 1.70) = 1 - P(Z < 1.70) = 1 - 0.9554 = 0.0446
( From z table)
P-value < 0.10 we reject null hypothesis.
b) one-tail test,
z = negative −2.45 and α = 0.02
P-value = P(Z < - 2.45) = 0.0071
( From z table)
P-value < 0.02 we reject null hypothesis.
c) two-tail test,
zx = 2.40, and α= .10
P-value = 2*P(Z > 2.40) = 0.0164
( From z table)
P-value < 0.10 we reject null hypothesis.
d) two-tail test,
zx = −1.24, and α = 0.05
P-value = 2*P(Z < - 1.24) = 2*0.1075 = 0.2150
( From z table)
P-value > 0.05 we fail to reject null hypothesis.
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