A sample average of size 14 is drawn from a normally distributed population and has a mean of 77 and a standard deviation of 14. Find the lower end, if 95% of all possible sample averages?
= 77
= 14
n = 14
SE = /
= 14/ = 3.7417
Lower end of 95% corresponds to area= 0.95 - 050 = 0.45 from mid value to Z on LHS.
Table of Area Under Standard Normal Curve gives Z = - 1.645
So,
Z = - 1.645 = ( - 77)/3.7417
So,
= 77 - (1.645 X 3.7417) = 70.8450
So,
Answer is:
70.8450
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