Question

Draw a normal probability distribution that would allow you to determine the likelihood of a measure falling within -3SD, -2SD and -1SD from the mean. Determine the likelihoods of each of the SD’s on the other side of the mean as well?

Answer 1

The graph of the normal probability distribution is below

From the above graph the likelihood of a measure falling within - 3SD from mean is (34.1+13.6+2.1)%=49.8%

The likelihood of a measure falling within - 2SD from mean is (34.1+13.6)%=47.7%

The likelihood of a measure falling within - 1SD from mean is 34.1%

Similarly the likelihood of a measure falling within 1SD from mean is 34.1%

The likelihood of a measure falling within 2SD from mean is (34.1+13.6)%=47.7%

The likelihood of a measure falling within 3SD from mean is (34.1 +13.6 +2.1) %=49.8%