Question

A nutrionist found that in a random sample of 80 families 25% indicated that they ate...

A nutrionist found that in a random sample of 80 families 25% indicated that they ate fruit at least 3 times a week. find the 99% confidence interval if the true proportions if families who said they ate fruit 3 times a week.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Suppose that a random sample 80 recent graduates of students is taken and it is found...
Suppose that a random sample 80 recent graduates of students is taken and it is found that 30 of them participated in an undergraduate research project while at school. a) Find a 99% confidence interval for the population proportion of students who participate in undergraduate research while at school. b) Using the fact that 30 out of the 80 graduates participated in undergraduate research, how large a sample of graduates is needed to arrive at a 99% confidence interval with...
In a random sample of 1000 families owning Netflix accounts in the charlottesville, it is found...
In a random sample of 1000 families owning Netflix accounts in the charlottesville, it is found that 688 watched the Spanish TV series “Money Heist’’. Find a 95% confidence interval for the actual proportion of families with Netflix accounts in charlottesville that watched “Money Heist”
In a random sample of 25 students, it was found that they consumed on average 23...
In a random sample of 25 students, it was found that they consumed on average 23 grams of sugar each day with a standard deviation of 4 grams. a) Construct a 99% confidence interval for the mean amount of sugar consumed by students. b) Interpret the confidence interval found in part a.
In a random sample of 25 ​people, the mean commute time to work was 30.6 minutes...
In a random sample of 25 ​people, the mean commute time to work was 30.6 minutes and the standard deviation was 7.2 minutes. Assume the population is normally distributed and use a​ t-distribution to construct a 95​% confidence interval for the population mean μ. What is the margin of error of μ​? Interpret the results. 1. The confidence interval for the population mean μ is (_,_) 2. The margin of error of μ is __ 3. Interpret the results. A.It...
HW 25 A random sample of 1300 home owners in a particular city found 143 home...
HW 25 A random sample of 1300 home owners in a particular city found 143 home owners who had a swimming pool in their backyard. Find a 95% confidence interval for the true percent of home owners in this city who have a swimming pool in their backyard. Express your results to the nearest hundredth of a percent. . Answer: ___ to ___ %
In a simple random sample of 1180 U.S. adults from a large population, it is found...
In a simple random sample of 1180 U.S. adults from a large population, it is found that 816 “regularly” spend more than 40 minutes per day checking email. Use this sample to estimate the true percentage, p, of all U.S. adults in this population who “regularly” spend more than 40 minutes per day checking email.In each question below, give answers as percents, rounded to at least two decimal places. (a) Find a 95% confidence interval for p % < p...
A survey is conducted with 25 families on the grocery budget of families and it’s determined...
A survey is conducted with 25 families on the grocery budget of families and it’s determined the mean budget is 452$ with a standard deviation of 95$. a) Find a 95% confidence interval of grocery budgets. b) Find a 99% confidence interval of grocery budgets. c) Which interval is larger? Why is that?
In a random sample of 250 Winnipeggers, 80 of them said they use transit. A 94%...
In a random sample of 250 Winnipeggers, 80 of them said they use transit. A 94% confidence interval for the true proportion of all Winnipeggers who use transit is: Note: Value of 90%(1.645 and 95%(1.960) is only provided in the table.
A poll found that 85% of a random sample of 1056 adults said that they believe...
A poll found that 85% of a random sample of 1056 adults said that they believe in ghosts. a. Determine the margin of error for a​ 99% confidence interval. b. Without doing any​ calculations, indicate whether the margin of error is larger or smaller for a​ 90% confidence interval.
In a random sample of 50 professional actors, it was found that 36 were extroverts. a....
In a random sample of 50 professional actors, it was found that 36 were extroverts. a. Let p represent the proportion of all actors who are extroverts. Find a point estimate p for p. b. Find a 99% confidence interval for p. c. Interpret the meaning of the confidence interval in the context of this problem.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT